4x^2-9/2x+3=5

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Solution for 4x^2-9/2x+3=5 equation: 


x in (-oo:+oo)

4*x^2-((9/2)*x)+3 = 5 // - 5

4*x^2-((9/2)*x)-5+3 = 0

4*x^2+(-9/2)*x-5+3 = 0

4*x^2-9/2*x-2 = 0

DELTA = (-9/2)^2-(-2*4*4)

DELTA = 209/4

DELTA > 0

x = ((209/4)^(1/2)+9/2)/(2*4) or x = (9/2-(209/4)^(1/2))/(2*4)

x = ((209/4)^(1/2)+9/2)/8 or x = (9/2-(209/4)^(1/2))/8

x in { (9/2-(209/4)^(1/2))/8, ((209/4)^(1/2)+9/2)/8 }

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